Activity: Soup Can

soup1

"Pi Soups Incorporated" want to sell soup in cylindrical cans that contain 400 ml.  

They also want to minimize the amount of metal in each can.

As the local mathematics expert it is your job to help them!

Volume and Surface Area

soup2

For a cylinder of height h and base radius r:

  • Surface Area = 2 × π × r × (r + h)
  • Volume = π × r2 × h

Which can be abbreviated to:

  • A = 2πr(r + h)
  • V = πr2h

Thickness of Metal

Let us assume that the metal has uniform thickness, so we just want to find

The smallest surface area that will hold 400 ml

Let us also assume that the thickness of the metal does not affect the volume (i.e. it is very small in comparison to the size of the can.)


To solve this we will work in centimeters, so:

  • the area will be measured in square centimeters (cm2) and
  • the volume will be measured in cubic centimeters (cm3).

This will make it easy, because 1ml is the same as a volume of 1cm3 - see the page Metric Volume.

So V = 400

This gives us the formula 400 = πr2h

Make h subject of the formula :

Divide both sides by πr2: 400/πr2 = h
Swap Sides: h = 400/πr2

Substitute this value for h into the formula for A:

A = 2πr(r+h) = 2πr(r + 400/πr2) = 2πr2 + 800/r

Now we know the Area in terms of the Radius:

A = 2πr2 + 800/r

This is our very simple Mathematical Model of the soup can.

Your Turn Now!

I have helped you enough. Now it is your turn.

You can use the formula above to investigate how changing the radius affects the area, and to find which radius gives the least area of metal.

You can make a report that explains things to everyone (pretend you will have to present this to a meeting of executives), with a graph and a table, and words.

Graph: draw the graph of the function, find the minimum value (you can use the Function Grapher)

Table: find example points on the graph by substituting different values of r.

For example, if r = 2, then A = 2π × 22 + 800/2 = 8π + 400 = 425 to the nearest whole number.

In other words, when the radius of the can is 2cm, the area of metal needed to make the can is 425cm2.

Put the example values into a table, like this one:

Radius Area Comments
0    
1    
2    
3    
4    
5    
6    
7    

Report: Put the graph and table together into a report, provide

  • an introduction,
  • an explanation
  • and your conclusions and recommendations.

A 1 Liter Can

What would be the best radius for a 1 Liter Can of soup?

 

Improving The Model

Air Gap

Soup cans are not completely filled with soup ... there is a small air gap on top. You can model this by adding (say) 1cm to the height.

Can you write the formula including this change?

How does this affect the graph, and the minimum value?

Rims

Soup cans have extra thick rims at top and bottom, how could you include this in the formula?