# Circle Equations

A circle is easy to make:

Draw a curve that is "radius" away
from a central point.

And so:

All points are the same distance
from the center.

In fact the definition of a circle is

Circle: The set of all points on a plane that are a fixed distance from a center.

## Circle on a Graph

Let us put a circle of radius 5 on a graph:

Now let's work out exactly where all the points are.

We make a right-angled triangle:

And then use Pythagoras:

x2 + y2 = 52

There are an infinite number of those points, here are some examples:

x y x2 + y2
5 0 52 + 02 = 25 + 0 = 25
3 4 32 + 42 = 9 + 16 = 25
0 5 02 + 52 = 0 + 25 = 25
−4 −3 (−4)2 + (−3)2 = 16 + 9 = 25
0 −5 02 + (−5)2 = 0 + 25 = 25

In all cases a point on the circle follows the rule x2 + y2 = radius2

We can use that idea to find a missing value

### Example: x value of 2, and a radius of 5

 Start with: x2 + y2 = r2 Values we know: 22 + y2 = 52 Rearrange: y2 = 52 − 22 Square root both sides:: y = ±√(52 − 22) Solve: y = ±√21 ≈ ±4.58...

(The ± means there are two possible values: one with + the other with )

And here are the two points:

## More General Case

Now let us put the center at (a,b)

So the circle is all the points (x,y) that are "r" away from the center (a,b).

Now lets work out where the points are (using a right-angled triangle and Pythagoras):

It is the same idea as before, but we need to subtract a and b:

(x−a)2 + (y−b)2 = r2

And that is the "Standard Form" for the equation of a circle!

It shows all the important information at a glance: the center (a,b) and the radius r.

### Example: A circle with center at (3,4) and a radius of 6:

(x−a)2 + (y−b)2 = r2

Put in (a,b) and r:

(x−3)2 + (y−4)2 = 62

We can then use our algebra skills to simplify and rearrange that equation, depending on what we need it for.

## "General Form"

But you may see a circle equation and not know it!

Because it may not be in the neat "Standard Form" above.

As an example, let us put some values to a, b and r and then expand it

 Start with: (x-a)2 + (y-b)2 = r2 Set (for example) a=1, b=2, r=3: (x-1)2 + (y-2)2 = 32 Expand: x2 - 2x + 1 + y2 - 4y + 4 = 9 Gather like terms: x2 + y2 - 2x - 4y + 1 + 4 - 9 = 0

And we end up with this:

x2 + y2 - 2x - 4y - 4 = 0

It is a circle equation, but "in disguise"!

So when you see something like that think "hmm ... that might be a circle!"

In fact we can write it in "General Form" by putting constants instead of the numbers:

x2 + y2 + Ax + By + C = 0

Note: the first two terms are always x2 + y2 .

## Going From General Form to Standard Form

Imagine we have an equation in General Form (like the example above):

x2 + y2 - 2x - 4y - 4 = 0

How can we get it into Standard Form like (x-a)2 + (y-b)2 = r2 ?

The answer is to Complete the Square (better read up on that!) ... for x and for y:

 Start with: x2 + y2 - 2x - 4y - 4 = 0 Put xs and ys together on left: (x2 - 2x) + (y2 - 4y) = 4 Now to complete the square we take half of the middle number, square it and add it. (Also add it to the right hand side so the equation stays in balance!) And do it for x and y. Do it for "x": (x2 - 2x + (-1)2) + (y2 - 4y) = 4 + (-1)2 And for "y": (x2 - 2x + (-1)2) + (y2 - 4y + (-2)2) = 4 + (-1)2 + (-2)2 Simplify: (x2 - 2x + 1) + (y2 - 4y + 4) = 9 Finally: (x - 1)2 + (y - 2)2 = 32

And we have it in Standard Form!

## Unit Circle

If we place the circle center at (0,0) and set the radius to 1 we get:

 (x-a)2 + (y-b)2 = r2 (x-0)2 + (y-0)2 = 12 x2 + y2 = 1 Which is the equation of the Unit Circle

## How to Plot a Circle by Hand

1. Plot the center (a,b)

2. Plot 4 points "radius" away from the center in the up, down, left and right direction

3. Sketch it in!

### Example: Plot (x-4)2 + (y-2)2 = 25

The formula for a circle is (x-a)2 + (y-b)2 = r2

So the center is at (4,2)

And r2 is 25, so the radius is √25 = 5

So we can plot:

• The Center: (4,2)
• Up: (4,2+5) = (4,7)
• Down: (4,2-5) = (4,-3)
• Left: (4-5,2) = (-1,2)
• Right: (4+5,2) = (9,2)

Now, just sketch in the circle the best we can!

## How to Plot a Circle on the Computer

We need to rearrange the formula so we get "y=".

We should end up with two equations (top and bottom of circle) that can then be plotted.

### Example: Plot (x-4)2 + (y-2)2 = 25

So the center is at (4,2), and the radius is √25 = 5

Rearrange to get "y=":

 Start with: (x-4)2 + (y-2)2 = 25 Move (x-4)2 to the right: (y-2)2 = 25 - (x-4)2 Take the square root: (y-2) = ± √[25 - (x-4)2] (notice the "plus/minus" ... there can be two square roots!) Move the "-2" to the right: y = 2 ± √[25 - (x-4)2]

Now, plot the two equations, and we should have a circle:

• y = 2 + √[25 - (x-4)2]
• y = 2 - √[25 - (x-4)2]

Have a look at the plot of this circle

It is also possible to use our Equation Grapher to do it all in one go.