# Continuous Functions

A function is continuous when its graph is a single unbroken curve ...

... that you could draw without lifting your pen from the paper.

That is not a formal definition, but it helps you understand the idea.

Here is a continuous function:

## Examples

So what is not continuous (also called discontinuous) ?

Look out for holes, jumps or vertical asymptotes (where the function heads up/down towards infinity).

 Not Continuous Not Continuous Not Continuous (hole) (jump) (vertical asymptote)

Try these different functions so you get the idea:

## Domain

 A function has a Domain. In its simplest form the domain is all the values that go into a function.

A function might be continuous or not, depending on its Domain!

### Example: 1/(x-1)

At x=1 we have:

1/(1-1) = 1/0 = undefined

So there is a "discontinuity" at x=1

 f(x) = 1/(x-1) over all Real Numbers g(x) = 1/(x-1) for x>1 NOT continuous Continuous

g(x) does not include the value x=1, so it is continuous.

So when a function is continuous within its Domain, it is a continuous function.

## More Formally !

We can define continuous using Limits (it helps to read that page first):

A function f is continuous when, for every value c in its Domain:

f(c) is defined, and:

"the limit of f(x) as x approaches c equals f(c)"

The limit says:

"as x gets closer and closer to c
then f(x) gets closer and closer to f(c)"

And we have to check from both directions:

 as x approaches c (from left) then f(x) approaches f(c) AND as x approaches c (from right) then f(x) approaches f(c)

If we get different values from left and right (a "jump"), then the limit does not exist!

## How to Use:

Make sure that, for all x values:

• f(x) is defined
• and the limit at x equals f(x)

Here are some examples:

### Example: f(x) = (x2-1)/(x-1) for all Real Numbers

 The function is undefined when x=1: (x2-1)/(x-1) = (12-1)/(1-1) = 0/0 So it is not a continuous function

Let us change the domain:

### Example: g(x) = (x2-1)/(x-1) over the interval x<1

Almost the same function, but now it is over an interval that does not include x=1.

So now it is a continuous function (does not include the "hole")

 which looks like:

It is defined at x=1, because h(1)=2 (no "hole")

But at x=1 you can't say what the limit is, because there are two competing answers:

• "2" from the left, and
• "1" from the right

so in fact the limit does not exist at x=1 (there is a "jump")

And so the function is not continuous.

But:

### Example: How about the piecewise function absolute value:

 which looks like:

At x=0 it has a very pointy change!

But it is still defined at x=0, because f(0)=0 (so no "hole"),

And the limit as you approach x=0 (from either side) is also 0 (so no "jump"),

So it is in fact continuous.

(But it is not differentiable.)