Order of Operations  BODMAS
Operations
"Operations" mean things like add, subtract, multiply, divide, squaring, etc. If it isn't a number it is probably an operation.
But, when you see something like...
7 + (6 × 5^{2} + 3)
... what part should you calculate first?
Start at the left and go to the right?
Or go from right to left?
Calculate them in the wrong order, and you will get a wrong answer !
So, long ago people agreed to follow rules when doing calculations, and they are:
Order of Operations
Do things in Brackets First. Example:
6 × (5 + 3)  =  6 × 8  = 
48 

6 × (5 + 3)  =  30 + 3  = 
33 
(wrong) 
Exponents (Powers, Roots) before Multiply, Divide, Add or Subtract. Example:
5 × 2^{2}  =  5 × 4  = 
20 

5 × 2^{2}  =  10^{2}  = 
100 
(wrong) 
Multiply or Divide before you Add or Subtract. Example:
2 + 5 × 3  =  2 + 15  = 
17 

2 + 5 × 3  =  7 × 3  = 
21 
(wrong) 
Otherwise just go left to right. Example:
30 ÷ 5 × 3  =  6 × 3  = 
18 

30 ÷ 5 × 3  =  30 ÷ 15  = 
2 
(wrong) 
How Do I Remember It All ... ? BODMAS !


B 
Brackets first 
O 
Orders (ie Powers and Square Roots, etc.) 
DM 
Division and Multiplication (lefttoright) 
AS 
Addition and Subtraction (lefttoright) 
Divide and Multiply rank equally (and go left to right).
Add and Subtract rank equally (and go left to right)
After you have done "B" and "O", just go from left to right doing any "D" or "M" as you find them. Then go from left to right doing any "A" or "S" as you find them. 
Note: the only strange name is "Orders". "Exponents" is used in Canada, and so you might prefer "BEDMAS". There is also "Indices" which makes it "BIDMAS". In the US they say "Parentheses" instead of Brackets, so it is "PEMDAS"
Examples
Example: How do you work out 3 + 6 × 2 ?
Multiplication before Addition:
First 6 × 2 = 12, then 3 + 12 = 15
Example: How do you work out (3 + 6) × 2 ?
Brackets first:
First (3 + 6) = 9, then 9 × 2 = 18
Example: How do you work out 12 / 6 × 3 / 2 ?
Multiplication and Division rank equally, so just go left to right:
First 12 / 6 = 2, then 2 × 3 = 6, then 6 / 2 = 3
Oh, yes, and what about 7 + (6 × 5^{2} + 3) ?
7 + (6 × 5^{2} + 3)  
7 + (6 × 25^{} + 3)  Start inside Brackets, and then use "Orders" First 
7 + (150^{} + 3)  Then Multiply 
7 + (153)  Then Add 
7 + 153  Brackets completed, last operation is add 
160  DONE ! 