# 24 from 8,8,3,3 Puzzle - Solution

### The Puzzle:

How can I get the answer 24 by only using the numbers 8,8,3,3.

You can use add, subtract, multiply, divide, and parentheses.

Bonus rules: also allowed are logarithms, factorials and roots

(Puzzle supplied by "Steve123")

You can use add, subtract, multiply, divide, and parentheses.

Bonus rules: also allowed are logarithms, factorials and roots

(Puzzle supplied by "Steve123")

### Our Solution:

1) Supplied by "mathsyperson":

8/(3-(8/3))

= 8/(1/3)

= 24

2) Supplied by "puzzler09" (using bonus rules):

((8 x 3!)/3)+8

= ((8 × 3 × 2 × 1)/3)+8

= (48/3)+8

= (16)+8

= 24

3) Supplied by "Mark" (using bonus rules):

(3!/)*8

4) Supplied by "Daryl S" (using bonus rules):

(8-3)!/(8-3)

( × )!

( + )!

√(8×8×3×3)

8+(8×(3!/3))

((√(8+8) × (3/3))!

√(8+8) × (3+3)

(log base(3!/3) of 8) × 8

((log base(3!/3) of (8+8))!

5) Supplied by "Sunil Prajapati" (using bonus rules):

√(8×8)×√(3×3) which is a variation of √(8×8×3×3) by Daryl S

8/(3-(8/3))

= 8/(1/3)

= 24

2) Supplied by "puzzler09" (using bonus rules):

((8 x 3!)/3)+8

= ((8 × 3 × 2 × 1)/3)+8

= (48/3)+8

= (16)+8

= 24

3) Supplied by "Mark" (using bonus rules):

(3!/)*8

4) Supplied by "Daryl S" (using bonus rules):

(8-3)!/(8-3)

( × )!

( + )!

√(8×8×3×3)

8+(8×(3!/3))

((√(8+8) × (3/3))!

√(8+8) × (3+3)

(log base(3!/3) of 8) × 8

((log base(3!/3) of (8+8))!

5) Supplied by "Sunil Prajapati" (using bonus rules):

√(8×8)×√(3×3) which is a variation of √(8×8×3×3) by Daryl S

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