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Kate and her Son's Age - Solution
Puzzles -> Algebra Puzzles
 The Puzzle: 5 years ago Kate was 5 times as old as her Son.
5 years hence her age will be 8 less than three times the corresponding age of her Son.
Find their ages.
(Puzzle contributed by "Pratibha") |
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The Solution . . .
First draw a table like this one below:
| | 5 YRS AGO | PRESENT | 5 YRS LATER |
|---|
| KATE | 5x | 5x + 5 | 5x + 10 |
| SON | x | x + 5 | x + 10 |
Now we know that 5 years from now Kate's age will be 8 less than three times the corresponding age of her Son! So, if we add 8 to Kate's age , 5 years from now, and make her Son's age 3 times more we will find out 'x' and PROBLEM SOLVED!
Therefore:
5x + 10 + 8 = 3(x + 10)
5x + 18 = 3x + 30
5x - 3x = 30 - 18
2x = 12
x = 12 / 2
x = 6
Now Kate's Present age is 5x + 5
=> 5(6) + 5
= 30 + 5
= 35 YEARS!!
Now her Son's Present age is x + 5
=> 6 + 5
= 11 YEARS!!
SOLVED!
(Solution contributed by "Pratibha") |
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