# Dot Product

A vector has **magnitude** (how long it is) and **direction**:

Here are two vectors:

They can be **multiplied** using the "**Dot Product**" (also see Cross Product).

## Calculating

The Dot Product gives a **number** as an answer (a "scalar", not a vector).

The Dot Product is written using a central dot:

**a** · **b**

This means the Dot Product of **a** and **b **

We can calculate the Dot Product of two vectors this way:

**a · b** = |**a**| × |**b**| × cos(θ)

Where:

|**a**| is the magnitude (length) of vector **a**

|**b**| is the magnitude (length) of vector **b
**θ is the angle between

**a**and

**b**

So we multiply the length of **a** times the length of **b**, then multiply by the cosine of the angle between **a** and **b**

OR we can calculate it this way:

**a · b** = a_{x} × b_{x} + a_{y} × b_{y}

So we multiply the x's, multiply the y's, then add.

Both methods work!

### Example: Calculate the dot product of vectors **a** and **b**:

**a · b** = |**a**| × |**b**| × cos(θ)

**a · b**= 10 × 13 × cos(59.5°)

**a · b**= 10 × 13 × 0.5075...

**a · b**= 65.98... = 66 (rounded)

**a · b** = a_{x} × b_{x} + a_{y} × b_{y}

**a · b**= -6

_{}× 5 + 8 × 12

**a · b**= -30 + 96

**a · b**= 66

Both methods came up with the same result (after rounding)

Also note that we used **minus 6** for a_{x} (it is heading in the negative x-direction)

Note: you can use the Vector Calculator
to help you.

## Why cos(θ) ?

OK, to multiply two vectors it makes sense to multiply their lengths together **but only when they point in the same direction****.**

So we make one "point in the same direction" as the other by multiplying by cos(θ):

We take the component of a that lies alongside b |
Like shining a light to see where the shadow lies |

THEN we multiply !

It works exactly the same if we "projected" Because it doesn't matter which order we do the multiplication: | |

## Right Angles

When two vectors are at right angles to each other the dot product is **zero**.

### Example: calculate the Dot Product for:

**a · b** = |**a**| × |**b**| × cos(θ)

**a · b**= |

**a**| × |

**b**| × cos(90°)

**a · b**= |

**a**| × |

**b**| × 0

**a · b**= 0

**a · b** = a_{x} × b_{x} + a_{y} × b_{y}

**a · b**= -12

_{}× 12 + 16 × 9

**a · b**= -144 + 144

**a · b**= 0

This can be a handy way to find out if two vectors are at right angles.

## Three or More Dimensions

This all works fine in 3 (or more) dimensions, too.

And can actually be very useful!

### Example: Sam has measured the end-points of two poles, and wants to know **the angle between them**:

We have 3 dimensions, so don't forget the z-components:

**a · b** = a_{x} × b_{x} + a_{y} × b_{y} + a_{z} × b_{z}

**a · b**= 9

_{}× 4 + 2 × 8 + 7 × 10

**a · b**= 36 + 16 + 70

**a · b**= 122

Now for the other formula:

**a · b** = |**a**| × |**b**| × cos(θ)

But what is |**a**| ? It is the magnitude, or length, of the vector **a**. We can use Pythagoras:

- |
**a**| = √(4^{2}+ 8^{2}+ 10^{2}) - |
**a**| = √(16 + 64 + 100) - |
**a**| = √180

Likewise for |**b**|:

- |
**b**| = √(9^{2}+ 2^{2}+ 7^{2}) - |
**b**| = √(81 + 4 + 49) - |
**b**| = √134

And we know from the calculation above that **a · b** = 122, so:

**a · b** = |**a**| × |**b**| × cos(θ)

^{-1}(0.7855...) = 38.2...°

Done!

I tried a calculation like that once, but worked all in angles and distances ... it was very hard, involved lots of trigonometry, and my brain hurt. The method above is much easier.

## Cross Product

The Dot Product gives a **scalar** (ordinary number) answer, and is sometimes called the **scalar product**.

But there is also the Cross Product which gives a **vector** as an answer, and is sometimes called the **vector product**.