Graphing Quadratic Equations
A Quadratic Equation in Standard Form
(a, b, and c can have any value, except that a can't be 0.)
Here is an example:
Graphing
You can graph a Quadratic Equation using our Function Grapher, but to really understand what is going on, you can make the graph yourself. Read On!
The Simplest Quadratic
The simplest Quadratic Equation is:
f(x) = x^{2}
And its graph is simple too:
This is the curve f(x) = x^{2}
It is a parabola.
Now let us see what happens when we introduce the "a" value:
f(x) = ax^{2}
 Larger values of a squash the curve
 Smaller values of a expand it
 And negative values of a flip it upside down
Play With ItNow is a good time to play with the "Quadratic Equation Explorer" so you can see what different values of a, b and c produce 
The "General" Quadratic
Before graphing we rearrange the equation, from this:
f(x) = ax^{2} + bx + c
To this:
f(x) = a(xh)^{2} + k
Where:
 h = b/2a
 k = f( h )
In other words, calculate h (=b/2a), then find k by calculating the whole equation for x=h
First of all ... Why?

So ...
 h shows you how far left (or right) the curve has been shifted from x=0
 k shows you how far up (or down) the curve has been shifted from y=0
Lets see an example of how to do this:
Example: Plot f(x) = 2x^{2 } 12x + 16
First, let's note down:
 a = 2,
 b = 12, and
 c = 16
Now, what do we know?
 a is positive, so it is an "upwards" graph ("U" shaped)
 a is 2, so it is a little "squashed" compared to the x^{2 }graph
Next, let's calculate h:
And next we can calculate k (using h=3):
So now we can plot the graph (with real understanding!):
We also know: the vertex is (3,2), and the axis is x=3
From A Graph to The Equation
What if you have a graph, and want to find an equation?
Example: you have just plotted some interesting data, and it looks Quadratic:
Just knowing those two points we can come up with an equation.
Firstly, we know h and k (at the vertex):
(h, k) = (1,1)
So let's put that into this form of the equation:
f(x) = a(xh)^{2} + k
f(x) = a(x1)^{2} + 1
Then we calculate "a":
We know (0, 1.5) so:  f(0) = 1.5  
And we know the function (except for a):  f(0) = a(01)^{2} + 1 = 1.5  
Simplify:  f(0) = a + 1 = 1.5  
a = 0.5 
And so here is the resulting Quadratic Equation:
f(x) = 0.5(x1)^{2} + 1
Note: This may not be the correct equation for the data, but itâ€™s a good model and the best we can come up with.