An example of a Quadratic Equation:
Quadratic Equations make nice curves, like this one:
The name Quadratic comes from "quad" meaning square, because the variable gets squared (like x2).
It is also called an "Equation of Degree 2" (because of the "2" on the x)
The Standard Form of a Quadratic Equation looks like this:
Here are some more examples:
|2x2 + 5x + 3 = 0||In this one a=2, b=5 and c=3|
|x2 − 3x = 0||
This one is a little more tricky:
|5x − 3 = 0||Oops! This one is not a quadratic equation: it is missing x2
(in other words a=0, which means it can't be quadratic)
Hidden Quadratic Equations!
So the "Standard Form" of a Quadratic Equation is
ax2 + bx + c = 0
But sometimes a quadratic equation doesn't look like that! For example:
|In disguise||→||In Standard Form||a, b and c|
|x2 = 3x − 1||Move all terms to left hand side||x2 − 3x + 1 = 0||a=1, b=−3, c=1|
|2(w2 − 2w) = 5||Expand (undo the brackets),
and move 5 to left
|2w2 − 4w − 5 = 0||a=2, b=−4, c=−5|
|z(z−1) = 3||Expand, and move 3 to left||z2 − z − 3 = 0||a=1, b=−1, c=−3|
Have a Play With It
Play with the "Quadratic Equation Explorer" so you can see:
How To Solve It?
The "solutions" to the Quadratic Equation are where it is equal to zero.
There are usually 2 solutions (as shown in the graph above).
They are also called "roots", or sometimes "zeros"
There are 3 ways to find the solutions:
Just plug in the values of a, b and c, and do the calculations.
We will look at this method in more detail now.
About the Quadratic Formula
First of all what is that plus/minus thing that looks like ± ?
The ± means there are TWO answers:
Here is why we can get two answers:
But sometimes we don't get two real answers, and the "Discriminant" shows why ...
Do you see b2 − 4ac in the formula above? It is called the Discriminant, because it can "discriminate" between the possible types of answer:
Complex solutions? Let's talk about them after we see how to use the formula.
Using the Quadratic Formula
Just put the values of a, b and c into the Quadratic Formula, and do the calculations.
Example: Solve 5x² + 6x + 1 = 0
|Coefficients are:||a = 5, b = 6, c = 1|
|Quadratic Formula:||x = −b ± √(b2 − 4ac) 2a|
|Put in a, b and c:||x = −6 ± √(62 − 4×5×1) 2×5|
|Solve:||x = −6 ± √(36 − 20) 10|
|x = −6 ± √(16) 10|
|x = −6 ± 4 10|
|x = −0.2 or −1|
Answer: x = −0.2 or x = −1
And we see them on this graph.
|Check -0.2:||5×(−0.2)² + 6×(−0.2) + 1
= 5×(0.04) + 6×(−0.2) + 1
= 0.2 − 1.2 + 1
|Check -1:||5×(−1)² + 6×(−1) + 1
= 5×(1) + 6×(−1) + 1
= 5 − 6 + 1
Remembering The Formula
I don't know of an easy way to remember the Quadratic Formula, but a kind reader suggested singing it to "Pop Goes the Weasel":
|♫||"x equals minus b||♫||"All around the mulberry bush|
|plus or minus the square root||The monkey chased the weasel|
|of b-squared minus four a c||The monkey thought 'twas all in fun|
|all over two a"||Pop! goes the weasel"|
Try singing it a few times and it will get stuck in your head!
Or you can remember this story:
x = −b ± √(b2 − 4ac) 2a
"A negative boy was thinking yes or no about going to a party,
at the party he talked to a square boy but not to the 4 awesome chicks.
It was all over at 2 am."
When the Discriminant (the value b2 − 4ac) is negative we get Complex solutions ... what does that mean?
It means our answer will include Imaginary Numbers. Wow!
Example: Solve 5x² + 2x + 1 = 0
|Coefficients are:||a = 5, b = 2, c = 1|
|Note that the Discriminant is negative:||b2 − 4ac = 22 − 4×5×1 = -16|
|Use the Quadratic Formula:||x = −2 ± √(−16) 10|
|The square root of -16 is 4i
(i is √-1, read Imaginary Numbers to find out more)
|So:||x = −2 ± 4i 10|
Answer: x = −0.2 ± 0.4i
The graph does not cross the x-axis. That is why we ended up with complex numbers.
In some ways it is easier: we don't need more calculation, just leave it as −0.2 ± 0.4i.
- Quadratic Equation in Standard Form: ax2 + bx + c = 0
- Quadratic Equations can be factored
- Quadratic Formula: x = −b ± √(b2 − 4ac) 2a
- When the Discriminant (b2−4ac) is:
- positive, there are 2 real solutions
- zero, there is one real solution
- negative, there are 2 complex solutions