Area of Triangles Without Right Angles
There are several ways to find the area of a triangle.
Knowing Base and Height
When we know the base and height it is easy.
It is simply half of b times h
Area = \frac{1}{2}bh
(The Triangles page explains more)
Example: What is the area of this triangle?
(Note: 12 is the height, not the length of the lefthand side)
Height = h = 12
Base = b = 20
Area = ½ bh = ½ × 20 × 12 = 120
Knowing Three Sides
There's also a formula to find the area of any triangle when we know the lengths of all three of its sides.
This can be found on the Heron's Formula page.
Knowing Two Sides and the Included Angle
When we know two sides and the included angle (SAS), there is another formula (in fact three equivalent formulas) we can use.
Depending on which sides and angles we know, the formula can be written in three ways:
Area = \frac{1}{2}ab sin C
Area = \frac{1}{2}bc sin A
Area = \frac{1}{2}ca sin B
They are really the same formula, just with the sides and angle changed.
Example: Find the area of this triangle:
First of all we must decide what we know.
We know angle C = 25º, and sides a = 7 and b = 10.
So let's get going:
How to Remember
Just think "abc": Area = ½ a b sin C
It is also good to remember that the angle is always between the two known sides, called the "included angle".
How Does it Work?
We know how to find an area when we know base and height:
Area = ½ × base × height
In this triangle:

So we get:
Area = ½ × (c) × (b × sin A)
Which is (more simply):
Area = \frac{1}{2}bc sin A
By changing the labels on the triangle we can also get:
 Area = ½ ab sin C
 Area = ½ ca sin B
One more example:
Example: Find How Much Land
Farmer Jones owns a triangular piece of land.
The length of the fence AB is 150 m. The length of the fence BC is 231 m.
The angle between fence AB and fence BC is 123º.
How much land does Farmer Jones own?
First of all we must decide which lengths and angles we know:
 AB = c = 150 m,
 BC = a = 231 m,
 and angle B = 123º
So we use:
Area = \frac{1}{2}ca sin B
Farmer Jones has 14,530 m^{2} of land